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anonymous

  • 5 years ago

hey can anyone help me with series/sequences? (algebra 2)

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  1. sandra
    • 5 years ago
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    hey what type of sequences/series?

  2. anonymous
    • 5 years ago
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    um not sure can i give u a problem and u try to help?

  3. anonymous
    • 5 years ago
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    ????

  4. sandra
    • 5 years ago
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    sure

  5. anonymous
    • 5 years ago
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    Write the series using summation notation. 7 + 10 + 13 + 16 + 19

  6. sandra
    • 5 years ago
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    ah ok. so the first number is 7, so that is a constant

  7. anonymous
    • 5 years ago
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    k...

  8. anonymous
    • 5 years ago
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    do i have to pay to get help on here??

  9. sandra
    • 5 years ago
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    \[\sum_{n=0}^{n=4} 7+3*n\] so something liek that?

  10. anonymous
    • 5 years ago
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    yes but how did u get that....

  11. sandra
    • 5 years ago
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    well, you are trying to make the summation equation part of it (the 7 + 3*n in this case), generate all of the numbers in the series if you input different values for "n". So given 7+10+13+16+19, you can start at the left. So if when n=0, the thing on the right is 7, then we know that 7 is a part of the summaition series

  12. anonymous
    • 5 years ago
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    oh

  13. sandra
    • 5 years ago
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    so then the question is , what can I add to 7, so when n=1 I'm adding 10, when n=2 I'm adding 13, and n=3 I'm added 16

  14. sandra
    • 5 years ago
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    so in fact my answer was wrong =)

  15. anonymous
    • 5 years ago
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    o...

  16. sandra
    • 5 years ago
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    or wait, sorry, I was right lol

  17. sandra
    • 5 years ago
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    ok so if n=0, and the right side is 7

  18. sandra
    • 5 years ago
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    and n=1, and the right side is 10

  19. sandra
    • 5 years ago
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    I've added 3

  20. sandra
    • 5 years ago
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    so my guess is that the right side is 7+3(n)

  21. sandra
    • 5 years ago
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    let's see if it holds true for n=2

  22. sandra
    • 5 years ago
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    for n=2, according to me, the third number is the series would be: 7 + (3*2) = 7+6 = 13

  23. sandra
    • 5 years ago
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    and so on..

  24. anonymous
    • 5 years ago
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    kk thanks!!!!!!!

  25. anonymous
    • 5 years ago
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    do i have to pay for this..

  26. anonymous
    • 5 years ago
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    no its free

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