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anonymous
 5 years ago
2 cars started from the same point and traveled on a straight course in opposite directions for exactly 2hrs at which time they were 208 miles apart. If 1 car traveled on average 8 miles per hour faster than the other, what was the averag speed for each car for the 2hr trip?
anonymous
 5 years ago
2 cars started from the same point and traveled on a straight course in opposite directions for exactly 2hrs at which time they were 208 miles apart. If 1 car traveled on average 8 miles per hour faster than the other, what was the averag speed for each car for the 2hr trip?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0If we let the slower car be traveling at x mph and the faster car be traveling at x+8, then we can figure out there speeds over 2 hours. 2(x+x+8)=208 > x+x+8=104 > 2x+8=104 > 2x=96 > x=48 mph. 48+(48+8) = 48 + 56 = 104 mph. 2 hrs * 104 miles = 208. So, slow car = 48 mph; fast car = 56 mph
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