## anonymous 5 years ago (x^1/9*x^4/9)^18/15

1. anonymous

is this your problem? $(x^\frac{1}{9}x^\frac{4}{9})^\frac{18}{15}$

2. anonymous

yea but you multiply the x's inside the parenthesis

3. anonymous

i got x^2/3

4. anonymous

$(x^ \frac{1}{9}*x^\frac{4}{9})^\frac{18}{15}$ is the same thing as$(x^ \frac{1}{9}x^\frac{4}{9})^\frac{18}{15}$ $(x^ \frac{1}{9}x^\frac{4}{9})^\frac{18}{15}= (x^\frac{5}{9})^\frac{18}{15}= x^\frac{90}{135}=x^\frac{2}{3}$

5. anonymous

6. anonymous

that's exactly how i did it thanks

7. anonymous

no prob

8. anonymous

can you help me on another one.?

9. anonymous

sure

10. anonymous

3$3\sqrt{2}+5\sqrt{2}$

11. anonymous

do i just add the 3 and 5?

12. anonymous

yeah but do you know why you can do that?

13. anonymous

because the square root is the same?

14. anonymous

yeah, so you could factor out the square root of 2$3\sqrt{2}+5\sqrt{2}=(3+5)\sqrt{2}=8\sqrt{2}$

15. anonymous

what happens if they aren't ... like this one: $6\sqrt{3}+10\sqrt{12}$

16. anonymous

think of how you can rewrite $10 \sqrt{12}$

17. anonymous

don't know

18. anonymous

so $10 \sqrt{12}= 10 \sqrt{4*3}= 10\sqrt{4}\sqrt{3}= 20\sqrt{3}$

19. anonymous

so now you have $6 \sqrt{3}+20 \sqrt{3}= (6+20)\sqrt{3}= 26\sqrt{3}$

20. anonymous

oooooooo okay now i get it so just get them to equal eachother

21. anonymous

yeah, thats the idea..... but its not always that easy to see it

22. anonymous

so like this one$2\sqrt{5}-3\sqrt{20}$

23. anonymous

im going to try it hold up

24. anonymous

oh my gosh.! i got it!

25. anonymous

$-4\sqrt{5}$ that's my answer

26. anonymous

nice.. thats right

27. anonymous

there's another one its actually harder kinda confusing can you help me out on this one also please

28. anonymous

sure

29. anonymous

$\sqrt[3]{3}+4\sqrt[3]{2}$

30. anonymous

yu there?

31. anonymous

yeah, do you know the answer by any chance?

32. anonymous

no but it's ok i 'll try my best 2mrw thanks n e way on the other ones huge help