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anonymous

  • 5 years ago

(x^1/9*x^4/9)^18/15

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  1. anonymous
    • 5 years ago
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    is this your problem? \[(x^\frac{1}{9}x^\frac{4}{9})^\frac{18}{15}\]

  2. anonymous
    • 5 years ago
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    yea but you multiply the x's inside the parenthesis

  3. anonymous
    • 5 years ago
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    i got x^2/3

  4. anonymous
    • 5 years ago
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    \[(x^ \frac{1}{9}*x^\frac{4}{9})^\frac{18}{15}\] is the same thing as\[(x^ \frac{1}{9}x^\frac{4}{9})^\frac{18}{15}\] \[(x^ \frac{1}{9}x^\frac{4}{9})^\frac{18}{15}= (x^\frac{5}{9})^\frac{18}{15}= x^\frac{90}{135}=x^\frac{2}{3}\]

  5. anonymous
    • 5 years ago
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    yeah your right

  6. anonymous
    • 5 years ago
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    that's exactly how i did it thanks

  7. anonymous
    • 5 years ago
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    no prob

  8. anonymous
    • 5 years ago
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    can you help me on another one.?

  9. anonymous
    • 5 years ago
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    sure

  10. anonymous
    • 5 years ago
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    3\[3\sqrt{2}+5\sqrt{2}\]

  11. anonymous
    • 5 years ago
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    do i just add the 3 and 5?

  12. anonymous
    • 5 years ago
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    yeah but do you know why you can do that?

  13. anonymous
    • 5 years ago
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    because the square root is the same?

  14. anonymous
    • 5 years ago
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    yeah, so you could factor out the square root of 2\[3\sqrt{2}+5\sqrt{2}=(3+5)\sqrt{2}=8\sqrt{2}\]

  15. anonymous
    • 5 years ago
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    what happens if they aren't ... like this one: \[6\sqrt{3}+10\sqrt{12}\]

  16. anonymous
    • 5 years ago
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    think of how you can rewrite \[10 \sqrt{12}\]

  17. anonymous
    • 5 years ago
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    don't know

  18. anonymous
    • 5 years ago
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    so \[10 \sqrt{12}= 10 \sqrt{4*3}= 10\sqrt{4}\sqrt{3}= 20\sqrt{3}\]

  19. anonymous
    • 5 years ago
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    so now you have \[6 \sqrt{3}+20 \sqrt{3}= (6+20)\sqrt{3}= 26\sqrt{3}\]

  20. anonymous
    • 5 years ago
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    oooooooo okay now i get it so just get them to equal eachother

  21. anonymous
    • 5 years ago
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    yeah, thats the idea..... but its not always that easy to see it

  22. anonymous
    • 5 years ago
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    so like this one\[2\sqrt{5}-3\sqrt{20}\]

  23. anonymous
    • 5 years ago
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    im going to try it hold up

  24. anonymous
    • 5 years ago
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    oh my gosh.! i got it!

  25. anonymous
    • 5 years ago
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    \[-4\sqrt{5}\] that's my answer

  26. anonymous
    • 5 years ago
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    nice.. thats right

  27. anonymous
    • 5 years ago
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    there's another one its actually harder kinda confusing can you help me out on this one also please

  28. anonymous
    • 5 years ago
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    sure

  29. anonymous
    • 5 years ago
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    \[\sqrt[3]{3}+4\sqrt[3]{2}\]

  30. anonymous
    • 5 years ago
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    yu there?

  31. anonymous
    • 5 years ago
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    yeah, do you know the answer by any chance?

  32. anonymous
    • 5 years ago
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    no but it's ok i 'll try my best 2mrw thanks n e way on the other ones huge help

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