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anonymous
 5 years ago
A 4.7 kΩ resistor dissipates 0.75 W. The voltage is
anonymous
 5 years ago
A 4.7 kΩ resistor dissipates 0.75 W. The voltage is

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[P=IV=V^{2}/R, V =\sqrt{PR}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am still confused because my professor didnt really teach us all of this and its also not in the book that we have so can you please help me a little more

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0W is watts, or power. 4.7kOhms is resistance. using the relationships above, you just plug the numbers into the right spot and you have your answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0P=ExI=ExE/R=E^2/R P=E^2/R 0.75W=E^2/4700 ohm E^2=0.75x4700 ohm E^2=3525 E=59.3 V

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, and \[IV=V ^{2}/R\]by using I=V/R from V=IR (where I is current in amps) remember 4.7kOhms is 4700 Ohms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok now i understand thank you so much now why couldn't my professor do this from the start lol thanks so much guys

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A parallel circuit contains four branches with resistors values of 4.7k, 5.6k, 8.1k and 10k. Which branch has the largest current flow

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The resistance in electronics is opposition of flow of electrical current.More resistance less current flow.Less resistance,more current flow.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To expand, in a parallel setup, the voltage drop across each resistor is the same, so you just employ V=IR. Smaller R means larger I
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