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anonymous
 5 years ago
How many license plates can you build with 3 letters and 3 numbers with repetitions? You also need the additive principle.
anonymous
 5 years ago
How many license plates can you build with 3 letters and 3 numbers with repetitions? You also need the additive principle.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.026*26*26*10*10*10 26 possible letters, 10 possible numbers. You can start with 26 different letters. For each, the next can be 26 different letters. For each of those, 26 possible letters. Then, for each of those, 10 possible numbers and so on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.026*26*26*10*10*10 26 possible letters, 10 possible numbers. You can start with 26 different letters. For each, the next can be 26 different letters. For each of those, 26 possible letters. Then, for each of those, 10 possible numbers and so on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that cant be right because there are only 3 letters and 3 numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you need to calculate possible ordering and remove new orders that duplicate. Try it and post if you get stuck

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where is the 26 and 10 coming from

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.026 letters in the alphabet, 10 different digits

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can only use 3 letters and 3 numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it doesnt say 26 numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think that means 3 of the characters on the plates are letters, and there are 26 different choices for each letter slot. Maybe I'm misunderstanding, but that is what the question would normally ask

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How many license plates can you build with 3 letters and three numbers with repetiion

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so im thinkink its sayying like letters {a,b,c} and numbers {1,2,3}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so MKV123 is 3 of each, but so is JHC567. Both are 3 of each, as is 1T2U4B

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the 26*26*26 thing was right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i have to use the additive princible

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, because you can start with a letter or a number which increases the permutations, then reduce that for the reorderings that end up duplicating a permutation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you show me how to do it im not understanding what to do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in your book, you have stuff like 3P26, 10C12 and that sort of thing. the 26 P 3 rather... 26 things taken 3 at a time. There will be a formula with it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but we can have repeats, so we are really using 26 P 1 three times

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which gives us the 26*26*26

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i figured that out im not sure where to go from there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you do 26*26*26*10*10*10 first. Then we can start with any of the three letters or numbers, yes? So 6 choices, then 5 for the next slot, 4 choices for the third slot and so on, and that ends up being 6! which we multiply our already big number by

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We would be done here except that we don't want to double count duplicates. if I have WWC567 and I swap the two Ws, then I don't actually have a new license number

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we need to figure out how many times that happens

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For any given arrangement, only swapping around letters or numbers with the same type could duplicate us. If I swap a letter and a number, I'm going to have a new arrangement.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is there anyone else that can jump in here? I need to run. I didn't think this would take a while.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This bit is where you use the combinations formulas to eliminate repeats

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm sorry, I have to meet friends in 10 minutes. Reread the examples in your book and see how far you get. Hopefully someone else will jump in!
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