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anonymous
 5 years ago
2x+4y2z=a and 3x6y+3z=b and x2y+z=c…I have reduced to 0x+0y+0z=a+2c and 0x+0y+0z=b+3c and x2y+z=c…how would one describe the solution? Is there even one?
anonymous
 5 years ago
2x+4y2z=a and 3x6y+3z=b and x2y+z=c…I have reduced to 0x+0y+0z=a+2c and 0x+0y+0z=b+3c and x2y+z=c…how would one describe the solution? Is there even one?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lets start like this. since x2y+z=c seems to be the simplest equation of the 3. Lets take that and solve for x or y, it doesn't matter which. once you have solved for x, take the solution, and plug it into 2x+4y2z=a. This will remove x out of this equation, then you can solve for y and plug it into the following equation. Try and work it out now.
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