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anonymous
 5 years ago
Summarize all pertinent information and sketch the graph of y = f(x):
f(x) = sqrt (25x^2)
anonymous
 5 years ago
Summarize all pertinent information and sketch the graph of y = f(x): f(x) = sqrt (25x^2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, so what is pertinent? Your square root argument must not be negative, which restricts your domain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Next, how does that restrict the domain? x^2 is always positive, so the biggest the square root part can be is 5, and the smallest is 0, so the range is 0<=y<=5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know what your teacher means by "pertinent information," but you can graph from there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Square both sides of the equation y=(25x^2) and rearrange the terms as shown below: \[y^2 + x^2=5^2\] I might be wrong but isn't that a circle, centered at the origin with a radius of 5?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the circle is not a function. You often can't just square both sides when it is a function. If the f(x) was really a y, then yes, it is a circle radius 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What we actually get looks to be the top half of that circle
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