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anonymous
 5 years ago
A cyclist rode From P to Q for 2 hours at an average speed of x km/h and then for 3/2 hours at (x3)km/h
a) Find in terms of x an expression for the distance of PQ.
After he had rested for half an hour at Q,he rode back from Q to P for 3 hours at the speed of (x+1) km/h
b)Find in terms of x,an expression of the distance PQ
c)Form an equation in x and find the distance of PQ
d)Find the average speed for the two way journey
anonymous
 5 years ago
A cyclist rode From P to Q for 2 hours at an average speed of x km/h and then for 3/2 hours at (x3)km/h a) Find in terms of x an expression for the distance of PQ. After he had rested for half an hour at Q,he rode back from Q to P for 3 hours at the speed of (x+1) km/h b)Find in terms of x,an expression of the distance PQ c)Form an equation in x and find the distance of PQ d)Find the average speed for the two way journey

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0distance = rate * time a) PQ = 2*x+(3/2)(x3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0c) we know the distance there = the distance back, so (2x+(3/2)(x3)=(x+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so x=11/5 from c, so the distance is 3*(11/5+1) PQ=3*(15/6)=15/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so using the total distance of 2*(15/2)=15km and the total time of 2+(3/2)+3hours we get 15km per 13/2 hours. Multiplying top and bottom by 2/13, we get 15*(2/13)=30/13 km/h

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0really sorry to interrupt you but for c),my answer booklet says it's 48km/h.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Your c here asks for a distance, not a rate, so something is wrong somewhere : )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I used (2x+(3/2)(x3)=3(x+1) instead of (2x+(3/2)(x3)=(x+1) and i got x=15..Then i substituted x=15 into 3(x+1) and got 48 km/h. Anyways, many thanks for your help :D really helped me to solve this qn.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ooh, I made a silly error!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nah..if not for your explanation about distance here = distance there,it would have taken me longer to solve this qn :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=3! Not 11/5. The explanation is right : )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, I just forgot a factor of 3 when I did my algebra to solve for x, so the numbers are off

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah but anyways,you bothered to help me :D so kind of you..Thanks again.
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