## anonymous 5 years ago use chain rule to evaluate ((3x)^2-5x)^-2/3

$\frac{d}{dx}[(3x)^2-5x)^{-2/3}]= \frac{d}{dx}[(9x^2-5x)^{-2/3}]$ $\frac{d}{dx}[(9x^2-5x)^{-2/3}]=\frac{-2(18x-5)}{3(9x^2-5x)^\frac{5}{3}}$