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anonymous
 5 years ago
what is integral of (cos x) / x ?
anonymous
 5 years ago
what is integral of (cos x) / x ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What integration techniques do you have right now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0usubstitution parts trig substitution etc.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just wanna find out derivative of cosx/x between 3 pi/2 and pi/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then the integral of cos x/x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The derivative would be the slope of the tangent line, the integral is the area of the region. Two different (yet related) things.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have tried finding out integral of cos x/x but it was an infinite loop!!! need an answer for this plz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have tried finding out integral of cos x/x but it was an infinite loop!!! need an answer for this plz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ntegration by parts is a heuristic rather than a purely mechanical process for solving integrals; given a single function to integrate, the typical strategy is to carefully separate it into a product of two functions ƒ(x)g(x) such that the integral produced by the integration by parts formula is easier to evaluate than the original one.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So it sounds like you tried parts. Which is what I would do. The integral ends up being: \[[\ln(x)\cos(x)+\sin(x)/x]/2 + c\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did u get that answer? can u plz explain the steps..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I set u = cos(x) and dv = dx/x and solved for du and v. Then I put in uv  ∫v du and had to use parts again using u = sin(x) and dv = ln(x)dx and solved for du and v again. This time I ended up with ln(x)cos(x)+sin(x)/x  ∫cos(x)/x dx = ∫cos(x)/x dx (the original problem) then I added ∫cos(x)/x dx to both sides and divide by two.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm..so derv of cos x =sinx and intg(dv) =1/x dx right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0du = sin(x)dx and v = ln(x) for the first parts.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the formula is , u int (v) int{d/dx(u) . int(v)}dx right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0∫u dv = u*v  ∫v du is what integration by parts states.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0intr(u) dv or integral (uv)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont we ve any formula as "something / somethig" in intergral as we ve for derivatives?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This integral cannot be represented in terms of transcendental and algebraic functions. You can only represent it with series.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if we have lower limit as pi/2 and upper one as 3 pi/2 then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0as the sin terms become all zeroes with pi/2 's

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It can't be done with any method other than series, even if you constrained the limits.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh..isnt there any other way out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not from what I researched online. You may be able to use power series. However, usubstitution, backwards usubstitution, integration by parts, partial fractions, etc. will not solve this integral. If I could remember power series from three years ago I could help, but I don't remember :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh :(...anyways thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0gotta findout frm somewhere else then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks Tbates and jshowa

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey can u just temme how do i join the group chat here??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have got lot many questions to ask....!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what you do, I tried typing something and it didn't work for me. You can just ask another question.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in such a case we get loops isnt it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0even if got the upper n lower limits for that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can anyone answer this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure, however, I intend on answering this question once I refresh myself with series. So, check back in a day or so. The limits really don't matter because you still have to evaluate the integral before you use them. And with integration by parts, you will continually get integrals that must be done with parts and it will never end. You must either construct a power series or Taylor series of cosx/x and estimate the integral.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah..that actually does go on n on..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0n theres one more thing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0n theres one more thing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tangent is a plane and normal is a line on that plane..is this staement correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0integration by parts would do it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0make 1/x your dv and and your u cos(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm...and how wud the final answer look like?
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