anonymous
  • anonymous
The first part of the 660 mile journey was by car at 30 mph. The 2nd part was by bus @ 60mph. If the total time was 14 hours, what was the distance traveled by bus?
Mathematics
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anonymous
  • anonymous
The first part of the 660 mile journey was by car at 30 mph. The 2nd part was by bus @ 60mph. If the total time was 14 hours, what was the distance traveled by bus?
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Let the time the car traveled be t. Then, using (distance)=(speed)*(time) for each part of the journey,\[660=30t+60(14-t)\]Solve for t. That's the time taken by the car. You need 'bus time', so subtract t from 14 hrs.
anonymous
  • anonymous
\[t_{bus}=8h\]
amistre64
  • amistre64
30x + 60y = 660; and x+y=14 (hours) x=(14-y) 30(14-y) +60y = 660 420 -30y +60y = 660 y(60-30) = 660-420 30y = 240 y= 240/30 = 24/3 = 8 The bus ride was 8 hrs long

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anonymous
  • anonymous
thanks!!!

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