Find y': y = (2x - 2)(3x + 1)

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Find y': y = (2x - 2)(3x + 1)

Mathematics
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It's probably easier to just expand the binomial and then differentiate term-by term. \[y = 6x^2-4x-1\] Differentiating that should be fairly easy.
are you please able to show the steps? i get that u expand the brackets and so on...
You need help with expanding from the parentheses or finding the derivative from y = 6x^2 - 4x - 1?

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expanding the parentheses
(2x - 2)(3x +1), you use the distributive property. The 3x + 1 is distributed to the 2x and to the -2... so (2x - 2)(3x+1) = 2x(3x+1) - 2(3x + 1) = 6x^2 + 2x - 6x + 1 = 6x^2 - 4x - 2... take the derivative of 6x^2 - 4x - 2.
great thank you heaps!!!
Wouldn't the actual expansion be:\[y=6x ^{2}-4x-2\]
Oh I see where gyasbic pointed that out, it wouldn't affect the answer anyway....would it
the final answer is 12x - 4

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