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anonymous

  • 5 years ago

Im getting confused with this:::: find the derivative of: r = 2/s^3 - 5/s

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  1. anonymous
    • 5 years ago
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    \[the derivative = 2x ^{-3}-5x ^{-1}\]

  2. anonymous
    • 5 years ago
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    an then you do this to derive it....

  3. anonymous
    • 5 years ago
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    \[derivative= -6x+5x ^{-2}\]

  4. anonymous
    • 5 years ago
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    the above is your answer

  5. anonymous
    • 5 years ago
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    or you can write the answer like this...

  6. anonymous
    • 5 years ago
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    \[derivative = -6x+(5/x ^{2})\]

  7. anonymous
    • 5 years ago
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    Fan me if that helped :D

  8. anonymous
    • 5 years ago
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    why does the 5/s change to 5s^-1?? can you please tell me how to change

  9. anonymous
    • 5 years ago
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    There is a rule with derivatives that says that if there is for example 5/s then you can write it as well as 5s^-1

  10. anonymous
    • 5 years ago
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    other examples are 288/x^7 = 288x^-7

  11. anonymous
    • 5 years ago
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    IF 5/s if equal to 5s^-1 then why is it 5s^-2??

  12. anonymous
    • 5 years ago
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    actually, its the rules of exponents. So when you have \[X ^{-a} = 1/(X ^{a})\]

  13. anonymous
    • 5 years ago
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    the negative sign represents the inverse.

  14. anonymous
    • 5 years ago
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    What I did there was following that rule where you multiply the exponent by the coefficient. so what I did was get =2x^(−3)−5x^(−1) using the rule of exponents. Then I multiplied the 2 in front of the x by the x's exponent (2X(-3)) = -6 then I subtracted 1 from the exponent -> (-3-1)= -4

  15. anonymous
    • 5 years ago
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    wow I just realised that I made a mistake

  16. anonymous
    • 5 years ago
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    the final answer should be -6x^(-4)+5x^(-2)

  17. anonymous
    • 5 years ago
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    sorry about that

  18. anonymous
    • 5 years ago
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    yeah so like I was saying before you subtract 1 from the exponents

  19. anonymous
    • 5 years ago
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    the final answer in the ANSWERS SHEET IS \[-6/s^{4} + 5/s^{2}\]

  20. anonymous
    • 5 years ago
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    in replying to your question above, \[r=(2/s ^{3}) - (5/s)\] \[r= 2s ^{-3} - 5s ^{-1}\] Find the derivative \[r'= (-3)(2s ^{-3-1}) - (-1)(5s ^{-1-1})\] \[r' = -6s ^{-4} + 5s ^{-2}\]

  21. anonymous
    • 5 years ago
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    thank you heaps... that is great ~ i can actually see what is happening :)

  22. anonymous
    • 5 years ago
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    no problem. calculus is very easy if you just follow all the rules properly =)

  23. anonymous
    • 5 years ago
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    do u no a good website where i can learn calculus quickly?

  24. anonymous
    • 5 years ago
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    Calculus is actually something best learned in the setting of a classroom. But if you have any questions to ask just ask here and ill be more than happy to assist you.

  25. anonymous
    • 5 years ago
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    great thanks heaps :)

  26. anonymous
    • 5 years ago
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    yup

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