The number of blues was two more than the total number of reds and greens. Three times the number of reds added to twice the number of greens was twice the number of blues. If there were 22 total. How many were there of each color?

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The number of blues was two more than the total number of reds and greens. Three times the number of reds added to twice the number of greens was twice the number of blues. If there were 22 total. How many were there of each color?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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b=2(r+g) 3r+2g=2b r+g+b=22
b: blues; g: greens; r: reds b = r + g + 2 2b = 3r + 2g r + g + b = 22 First equation: b - 2 = r + g Third equation: b - 2 + b = 22 --> 2b = 24 --> b = 12 First equation: 12 = r + g + 2 --> r + g = 10 --> 3r + 3g = 30 Second equation: 24 = 3r + 2g --> 3r + 2g = 24 First equation - second equation: g = 6 6 + r = 10 --> r = 4 12 green, 4 red, 6 blue
oh whoops mine was off

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