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anonymous
 5 years ago
The number of blues was two more than the total number of reds and greens. Three times the number of reds added to twice the number of greens was twice the number of blues. If there were 22 total. How many were there of each color?
anonymous
 5 years ago
The number of blues was two more than the total number of reds and greens. Three times the number of reds added to twice the number of greens was twice the number of blues. If there were 22 total. How many were there of each color?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b=2(r+g) 3r+2g=2b r+g+b=22

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b: blues; g: greens; r: reds b = r + g + 2 2b = 3r + 2g r + g + b = 22 First equation: b  2 = r + g Third equation: b  2 + b = 22 > 2b = 24 > b = 12 First equation: 12 = r + g + 2 > r + g = 10 > 3r + 3g = 30 Second equation: 24 = 3r + 2g > 3r + 2g = 24 First equation  second equation: g = 6 6 + r = 10 > r = 4 12 green, 4 red, 6 blue

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh whoops mine was off
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