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anonymous
 5 years ago
Find implict differentiation
√xy = 2 + x2y
anonymous
 5 years ago
Find implict differentiation √xy = 2 + x2y

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm assuming you want dy/dx and that the y is not under the square root and the x is squared. \[1/2(x^{1/2})y+x ^{1/2}y'=0+2xy+x^2y'\] \[x ^{1/2}y'x^2y'=2xyy/(2x ^{1/2})\] \[y'(x ^{1/2}x^2)=2xyy/(2x ^{1/2})\] \[y'=(2xy0.5x ^{0.5}y)/(x ^{0.5}x^2)\] \[y'=[(0.5x ^{0.5}(4x ^{1.5}yy))/(x ^{0.5}(xx^2.5)]\] \[y'=(4x \sqrt{x}yy)/(2x2x^2\sqrt{x})\] Sorry, that took a while. I put it in the neatest form I think I could... though you could factor out a 2x on the bottom.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank You So much for your timely help.
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