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anonymous
 5 years ago
Find four consecutive intergers such that the product of the 1st interger and the 3rd interger is 25 greater than the product of 13 and the fourth integer
Answers: 14,13,12,11
anonymous
 5 years ago
Find four consecutive intergers such that the product of the 1st interger and the 3rd interger is 25 greater than the product of 13 and the fourth integer Answers: 14,13,12,11

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let’s say that your sequence of four numbers starts at some number n. Then the four numbers are n, n+1, n+2, and n+3. You’re asked to find that number n so that n(n+2) = 25 + (13)(n+3). One way to solve this is to notice that this is a quadratic equation in n. You’re guaranteed that an integer solution exists, so you’d expect to be able to factor the quadratic expression. If you try, you’ll simplify it down to n^2 + 15n + 14 = 0. And this is (n + 14)(n + 1) = 0. So n can be either 14 or 1. If n = 14, then you get the sequence 14, 13, 12, 11. If you let n = 1, then you get the sequence 1, 0, 1, 2. You can check that both sequences satisfy our condition on the numbers.
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