Find an equation of the tangent line at the indicated point on the graph of the function. y = f(x) = x2 - x, (x, y) = (2, 2)

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Find an equation of the tangent line at the indicated point on the graph of the function. y = f(x) = x2 - x, (x, y) = (2, 2)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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To know the equation of a tangent line, you need two things. 1) You need the slope of the line. That's found by finding the derivative of the function and evaluating it at the point. 2) You also need a point that the tangent line goes through. But you already know that the tangent line passes through the point you're given. So you have that information as well. Knowing the point and slope, you can use the point-slope form of a line to write the equation of the tangent line.
dy/dx=2x-1, it is the slope of line at any point, so at {2,2} it will be 3. now equation of line... (y-2)=3(x-2) 3x-y-4=0

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