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anonymous
 5 years ago
find P(N'M')
P(M)=.07, P(NM)=.2, P(NM')=.3
anonymous
 5 years ago
find P(N'M') P(M)=.07, P(NM)=.2, P(NM')=.3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The notation is fuzzy for me. Am I correct in saying that N' is the complement of N and M' is the complement of M? Anyway, the probability of P(N'M') = 1  P(NM'), so P(N'M') = 1  .3 = .7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ims sorry its actually, find P(N'M') P(M)=.7, P(NM)=.2, P(NM')=.3 and it is the complement of m and n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, then it should be P(N'M') = .7 P(NM') is the probability of N occurring given that M' has occurred. The probability that P(NM') would not occur is 1  .3 = .7
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