anonymous
  • anonymous
Find dy/dx by implicit differentiation" xe^y-10x+3y=0 i really do need help!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
implicit differentation means you assume y is a function of x: Dx(xe^y) -Dx(10x) +Dx(3y) = Dx(0) Dx(xe^y) use the product rule: (dx/dx)e^y + (dy/dx)xe^y = e^y + y'xe^y Dx(10x) = (dx/dx)(10) = 10 Dx(3y) = 3(dy/dx) = 3y' Dx(0) = (d0/dx)0 = 0 Get all your y' on one side and everything else to the other: e^y + y'xe^y -10 +3y' = 0 y'xe^y + 3y' = 10 -e^y y'(xe^y +3) = 10 -e^y (dy/dx) =y' =(10-e^y) / (xe^y +3) That should be it :)
anonymous
  • anonymous
omg!! thank you so much!!!
amistre64
  • amistre64
Implicits confused me at first; but they are just like ll the rest :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
im a lil confused, but im gonna keep studying thank you again
anonymous
  • anonymous
gratz

Looking for something else?

Not the answer you are looking for? Search for more explanations.