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anonymous
 5 years ago
Find dy/dx by implicit differentiation"
xe^y10x+3y=0
i really do need help!
anonymous
 5 years ago
Find dy/dx by implicit differentiation" xe^y10x+3y=0 i really do need help!

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0implicit differentation means you assume y is a function of x: Dx(xe^y) Dx(10x) +Dx(3y) = Dx(0) Dx(xe^y) use the product rule: (dx/dx)e^y + (dy/dx)xe^y = e^y + y'xe^y Dx(10x) = (dx/dx)(10) = 10 Dx(3y) = 3(dy/dx) = 3y' Dx(0) = (d0/dx)0 = 0 Get all your y' on one side and everything else to the other: e^y + y'xe^y 10 +3y' = 0 y'xe^y + 3y' = 10 e^y y'(xe^y +3) = 10 e^y (dy/dx) =y' =(10e^y) / (xe^y +3) That should be it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0omg!! thank you so much!!!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Implicits confused me at first; but they are just like ll the rest :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im a lil confused, but im gonna keep studying thank you again
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