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anonymous
 5 years ago
how can i do the derivates of
(x+1)^3/x3/2
anonymous
 5 years ago
how can i do the derivates of (x+1)^3/x3/2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is this the function? \[(x + 1)^3/x ^{3/2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok... rewrite: \[y = (x + 1)^3x ^{3/2}\] Product rule: \[y'= 3(x + 1)^2(1)x ^{3/2}+(x+1)^3(3/2)x ^{5/2}\] \[y'=(x+1)^2x ^{3/2}[3+(3/2)(x+1)x ^{1}]\] \[y'=(x+1)^2[3/23/(2x)]/x ^{3/2}\] \[y'=(x+1)^2[(3x3)/(2x)]/x ^{3/2}\] \[y'=3(x1)(x+1)^2/(2x ^{5/2})\] Someone else may wanna check this over, though...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yup I checked. It's definitely right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got lost on the second line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0On the second line I factored out (x + 1)^2 and x^(3/2).
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