P = the number of fish X = the number of months the fish were placed in the aquarium What is the total number of fish? P(x) = 90(1 + 1.5x)/1 + 0.5x

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P = the number of fish X = the number of months the fish were placed in the aquarium What is the total number of fish? P(x) = 90(1 + 1.5x)/1 + 0.5x

Mathematics
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is it (90 + 135x)/(1+.5x) in expanded form? Are you looking for a maximium number of fish possible? As in, if you graphed the equation in expanded form, the highest point on the graph with the domain (0,infinity)?
yes
Ok, so what I did was took a graphing calculator, you can use any of them. (Ti-83 and above for texas instruments calculators I think) I went to the top left button which is Y= (the "y editor") Typed in to the first y= line the following "(90+135*x)/(1+.5*x) Then went to window and extended the domain (x axis display) to 0, +50 and the y axis display (range) to 0, +50 Then I graphed it. I found that the y-values were much greater than 50, so I went back to my windows tab and changed the maximum to 500 and the x-max to 100. I found that it creates an asymptote at approximately equal to 270, with P(999) equal to 269.64 and very slowly approaching 270. So. It would appear your answer is 270, if the maximum number of fish sustainable by the system is what you are seeking to find. The prompt wasn't very specific though.

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