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anonymous

  • 5 years ago

please help 2yx=7y+5 with point (-9,2) in slope intercept form

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  1. Vijay
    • 5 years ago
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    your points are not satisfy with equation.

  2. anonymous
    • 5 years ago
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    i'm trying to help a friend 300 miles from me... but it's been forever since i've taken a math class

  3. anonymous
    • 5 years ago
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    y=5/2x-7+9/5

  4. anonymous
    • 5 years ago
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    how did you come to that

  5. Vijay
    • 5 years ago
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    Actually this equation looks parabola ( not straight line )

  6. anonymous
    • 5 years ago
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    well using the equation y=mx+b for the slope intercept form you solve for b by plugging in the point (-9,2) to the equation y=5/2x-7 the -9 is your x and 2 is your y value.

  7. anonymous
    • 5 years ago
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    i am assuming you want it to pass through the point (-9,2) or it would not work since at x=-9 y does not equal 2 as vijay said it would not satisfy the equation

  8. anonymous
    • 5 years ago
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    right it needs to pass through that point

  9. Vijay
    • 5 years ago
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    Felee, It will not go through the point, and this a parabolic equation. If you draw the graph , u will understand more about it.

  10. anonymous
    • 5 years ago
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    so if i were to simplify that equation it would be y=5/2x-8.8 ?????

  11. anonymous
    • 5 years ago
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    no the the -7 is part of the mx it needs to stay under the 5 its part of the slope. all you can do to simplify in these case is turn the 9/5 into a decimal Y=5/(2x-7)+1.8

  12. anonymous
    • 5 years ago
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    ok thank you i will pass this info along to my friend :)

  13. Vijay
    • 5 years ago
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    nooooooooooooo, mr, cal2 student u r wrong u cannot make this eqution to y = mx+c format because , this is not straight line

  14. anonymous
    • 5 years ago
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    Thank you all for your help I'll pass it along

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