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anonymous
 5 years ago
find dy/dx where xy^33x^2=7y
anonymous
 5 years ago
find dy/dx where xy^33x^2=7y

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am not sure how to work it. I just started working on these kind of problems. My examples are confusing. I have (x+3xy) 3x^2=7 to start off with, is that correct?

Vijay
 5 years ago
Best ResponseYou've already chosen the best response.0No, this is partial differentiation, it is not like other differentiation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its Implicit differentiation, partials are when you hold one variable as a constant. In Implicit differentiation you take the derivative of both variables with respect to x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here's the work: \[xy^33x^2=7y \rightarrow y^3+3xy^2\frac{dy}{dx}6x=7\frac{dy}{dx}\] \[\rightarrow y^36x=7\frac{dy}{dx}3xy^2\frac{dy}{dx}\] \[\rightarrow y^36x=(73xy^2)\frac{dy}{dx}\] \[\frac{dy}{dx}=\frac{y^36x}{73xy^2}\]
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