## anonymous 5 years ago Solve the given equation and indicate the number of values of θ sach that 0≤θ<2π satisfy the iquation 2sin^2(θ)-sinθ-1=

1. anonymous

hey, how's it going?

2. anonymous

alma1969, is your equation $2\sin^2{\theta}-\sin{\theta}-1=0$? It needs to equal something before it can be solved...

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