anonymous
  • anonymous
A dish has 200 pieces of candy, of which 20% are M&M's. Of these M&M's, 30% are blue, 50% are red, and 20% are green. Kenya takes 40 pieces and Justin takes 100 pieces at random. How many more red M&M's would we expect Justin to have than Kenya?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
50% of 40 is 20 50% of 100 is 50 50 - 20 ?
anonymous
  • anonymous
so would it be 30 more?
anonymous
  • anonymous
y

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anonymous
  • anonymous
50 minus 20?
amistre64
  • amistre64
K has 40 pieces (assume 20% of them are MMs) K=40(.2) = 8 MMs. 50% of her MMs are red: 4 MMs J= 100(.2) = 20 MMs. 50% of his MMs are red: 10 MMs J could have 6 more MMs than K
anonymous
  • anonymous
Thank you
amistre64
  • amistre64
no prob.

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