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anonymous

  • 5 years ago

A dish has 200 pieces of candy, of which 20% are M&M's. Of these M&M's, 30% are blue, 50% are red, and 20% are green. Kenya takes 40 pieces and Justin takes 100 pieces at random. How many more red M&M's would we expect Justin to have than Kenya?

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  1. anonymous
    • 5 years ago
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    50% of 40 is 20 50% of 100 is 50 50 - 20 ?

  2. anonymous
    • 5 years ago
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    so would it be 30 more?

  3. anonymous
    • 5 years ago
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    y

  4. anonymous
    • 5 years ago
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    50 minus 20?

  5. amistre64
    • 5 years ago
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    K has 40 pieces (assume 20% of them are MMs) K=40(.2) = 8 MMs. 50% of her MMs are red: 4 MMs J= 100(.2) = 20 MMs. 50% of his MMs are red: 10 MMs J could have 6 more MMs than K

  6. anonymous
    • 5 years ago
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    Thank you

  7. amistre64
    • 5 years ago
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    no prob.

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