A dish has 200 pieces of candy, of which 20% are M&M's. Of these M&M's, 30% are blue, 50% are red, and 20% are green. Kenya takes 40 pieces and Justin takes 100 pieces at random. How many more red M&M's would we expect Justin to have than Kenya?

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A dish has 200 pieces of candy, of which 20% are M&M's. Of these M&M's, 30% are blue, 50% are red, and 20% are green. Kenya takes 40 pieces and Justin takes 100 pieces at random. How many more red M&M's would we expect Justin to have than Kenya?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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50% of 40 is 20 50% of 100 is 50 50 - 20 ?
so would it be 30 more?
y

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Other answers:

50 minus 20?
K has 40 pieces (assume 20% of them are MMs) K=40(.2) = 8 MMs. 50% of her MMs are red: 4 MMs J= 100(.2) = 20 MMs. 50% of his MMs are red: 10 MMs J could have 6 more MMs than K
Thank you
no prob.

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