simplify: the little 3 over the square root of 32x^5y^9
Stacey Warren - Expert brainly.com
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That's called a cube root. It's the same as raising the quantity to the power of 1/3. (A square root is to the power of 1/2)
32 = 2^5
32^(1/3) = 2^(5/3)
(x^5)^(1/3) = x^(5/3)
(y^9)^(1/3) = y^3
2^(5/3) * x^(5/3) * y^3 is the most simplified answer
is that how it is written in radical notation?
I'm not using radicals. I'm raising them to exponents to forgo any problems of communicating how to write that as a radical. Do you need it in radical notation?
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yes that is where i get confused.
... is there a way to solve for radical notation?
Sorry about not getting back to you.
given the final answer of: 2^(5/3) * x^(5/3) * y^3
You can write the radical sign with the 3, denoting a cube root, with 32*x^5*y^9 within it, and that would be in radical form.
However, you can further simplify it still while maintaining radical form. Such as:
2^(5/3) pulled out of the radical.
Also, y^(9/3) is equal to y^3
So you have y^3 * 2^(5/3) * cube root(x^5).
Or you can have y^3 * cuberoot(32*x^5).
Choose whichever you think is most applicable in your case.
THANKS! honestly your descriptions are helping me out!!