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anonymous
 5 years ago
solve for K: log base 4 (5k+4)=3
anonymous
 5 years ago
solve for K: log base 4 (5k+4)=3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04(5k+4)=3 20k+16=3 16 16 20k=13/20 check: 4(5(13/20)+4)=3 k=13/20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks , so whenever you hvae log base ___ (any given #) you just multiply that out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I do not know :/ sorry I just worked out the problem which like that it gives me the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually, do it like this: log_4(5k+4)=3 5k+4=4^3 5k=4^34 k=12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am confused.... what does the log_4 do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since you have the log with base 4, if you raise the entire left side of the equation to be an exponent of the base, it will drop out and you will be left with the inside of the log function. For example. 10^log_(10)(x) = x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the 4 is then placed inside the eqation...?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the 4 is the base of the logarithm. it defines how the logarithm behaves.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if i had an equation that was like log_6 (eq) =2 then i would make it 6^2 ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah pretty much. you would end up with (eq)=6^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. great thanks :) are you good with logs?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am. I'm just about to graduate the University of Arizona with a degree in Applied Math. Shoot me an email if you need more help ajkelly@email.arizona.edu
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