anonymous
  • anonymous
solve for K: log base 4 (5k+4)=3
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
4(5k+4)=3 20k+16=3 -16 -16 20k=-13/20 check: 4(5(-13/20)+4)=3 k=-13/20
anonymous
  • anonymous
thanks , so whenever you hvae log base ___ (any given #) you just multiply that out?
anonymous
  • anonymous
I do not know :/ sorry I just worked out the problem which like that it gives me the answer

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anonymous
  • anonymous
actually, do it like this: log_4(5k+4)=3 5k+4=4^3 5k=4^3-4 k=12
anonymous
  • anonymous
i am confused.... what does the log_4 do?
anonymous
  • anonymous
since you have the log with base 4, if you raise the entire left side of the equation to be an exponent of the base, it will drop out and you will be left with the inside of the log function. For example. 10^log_(10)(x) = x
anonymous
  • anonymous
so the 4 is then placed inside the eqation...?
anonymous
  • anonymous
the 4 is the base of the logarithm. it defines how the logarithm behaves.
anonymous
  • anonymous
so if i had an equation that was like log_6 (eq) =2 then i would make it 6^2 ??
anonymous
  • anonymous
yeah pretty much. you would end up with (eq)=6^2
anonymous
  • anonymous
ok. great thanks :) are you good with logs?
anonymous
  • anonymous
I am. I'm just about to graduate the University of Arizona with a degree in Applied Math. Shoot me an email if you need more help ajkelly@email.arizona.edu

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