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anonymous

  • 5 years ago

solve for K: log base 4 (5k+4)=3

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  1. anonymous
    • 5 years ago
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    4(5k+4)=3 20k+16=3 -16 -16 20k=-13/20 check: 4(5(-13/20)+4)=3 k=-13/20

  2. anonymous
    • 5 years ago
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    thanks , so whenever you hvae log base ___ (any given #) you just multiply that out?

  3. anonymous
    • 5 years ago
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    I do not know :/ sorry I just worked out the problem which like that it gives me the answer

  4. anonymous
    • 5 years ago
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    actually, do it like this: log_4(5k+4)=3 5k+4=4^3 5k=4^3-4 k=12

  5. anonymous
    • 5 years ago
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    i am confused.... what does the log_4 do?

  6. anonymous
    • 5 years ago
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    since you have the log with base 4, if you raise the entire left side of the equation to be an exponent of the base, it will drop out and you will be left with the inside of the log function. For example. 10^log_(10)(x) = x

  7. anonymous
    • 5 years ago
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    so the 4 is then placed inside the eqation...?

  8. anonymous
    • 5 years ago
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    the 4 is the base of the logarithm. it defines how the logarithm behaves.

  9. anonymous
    • 5 years ago
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    so if i had an equation that was like log_6 (eq) =2 then i would make it 6^2 ??

  10. anonymous
    • 5 years ago
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    yeah pretty much. you would end up with (eq)=6^2

  11. anonymous
    • 5 years ago
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    ok. great thanks :) are you good with logs?

  12. anonymous
    • 5 years ago
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    I am. I'm just about to graduate the University of Arizona with a degree in Applied Math. Shoot me an email if you need more help ajkelly@email.arizona.edu

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