anonymous 5 years ago find all the values of x which are solutions. A. x2 + 2= 27 B.-5|x| = -15

B. $-\left| x \right|=-15$

messed up left off the 5.$-5\left| x \right|=-15$

$\left| x \right|=-15$

$\left| x \right|=15$

Please ignore the above last two entries.$\left| x \right|=-15\div-5=3$

$x=\pm3$

Now for A.$x ^{2}+2=27$ $x ^{2}=27-2=25$ $x=\sqrt{25}=\pm5$