## anonymous 5 years ago (12y^3 + 9 y^2 + 21y) ÷ 3y Simplify with steps.

1. Vijay

4Y^2+3Y+7

2. anonymous

${{12y^3+9y^2+21y}\over{3y}}$ Factor out a "y" ${{y}\over{y}} \times {{12y^2+9y+21}\over{3}}$ Now lets factor out a "3" ${{3}\over{3}} \times {{4y^2+3y+7}\over{1}}$ So our final answer is: $4y^2+3y+7$