anonymous
  • anonymous
algebra 1b solve by factoring 3x squared + 7x-6=0
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
(3x - 2) (x + 2) = 0
anonymous
  • anonymous
i mean (3x-2) ( x + 3)
anonymous
  • anonymous
\[3x ^{2}+7x-6\]

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vijay
  • vijay
x=2/3 and -3
anonymous
  • anonymous
how do you get that. i really need to understand
anonymous
  • anonymous
trial and error you can also use quadratic equation
vijay
  • vijay
3x^2 + 7x-6=0 3x^2 + 9x-2x-6=0 3x(x+3)-2(x+3)=0 (x+3)(3x-2)=0
anonymous
  • anonymous
\[step 1. (x+9)(x-2) step 2??\]
vijay
  • vijay
(x+3)(3x-2)=0 (x+3) = 0 and 3x-2 = 0 x = -3 and x = 2/3
anonymous
  • anonymous
how did you get (x+3)(3x-2) ????
vijay
  • vijay
from this line 3x(x+3)-2(x+3)=0 if u factorise (x+3) , u may get
anonymous
  • anonymous
correction: how did you get \[3x ^{2}+7x-6=0\]
anonymous
  • anonymous
sorry im confusing myself .
anonymous
  • anonymous
my teacher makes us do a big x. so what multiplies to -12 and adds to 7. i got 9 and -2 so (x+9) (x-2) how do i go on from there
vijay
  • vijay
can u type your question again with mathematical symbols ?
anonymous
  • anonymous
solve by factoring \[3x ^{2}+7x-6=0\] step one. FACTOR. multiply -6 and 3 to get -18. now find what multiplies to -18 make sure that they also add to get 7. 9 and -2 MULTIPLY together and make -18 and ADD to make 7. so you make the equation (x+9)(x-2)=0 but you still have to do more for the rest of the problem. so im confused on the rest
vijay
  • vijay
substitute your -9 and 2 for 7
vijay
  • vijay
sorry 9 and -2
anonymous
  • anonymous
so it would be \[3x ^{2}+(x+9)(x-2)-6=0 ?\] that makes no sense
vijay
  • vijay
no, \[3x^2 +9x - 2x -6=0\]
anonymous
  • anonymous
so what do i do to solve that? add like terms?
vijay
  • vijay
then,. factorise 3x from from 1st two terms ans factorise 2 from last two terms
anonymous
  • anonymous
3x(x+3) -2(x+3)
vijay
  • vijay
yes, then factorise (x+3)
anonymous
  • anonymous
wait so how to i solve the rest of the problem
vijay
  • vijay
then, each of them equal to zero
anonymous
  • anonymous
3x(x+3)=0 -2(x+3)=0
vijay
  • vijay
no, when u factorise by ( x-3), u will get (x-3)(3x-2) = 0
vijay
  • vijay
After that make, x-3 = 0 and 3x- 2 = 0
anonymous
  • anonymous
howd you get (x-3) and (3x-2)
vijay
  • vijay
from 3x(x+3) -2(x+3) = 0, factorise (x+3)
vijay
  • vijay
take out x+3 , then 3x-2 is other balance
anonymous
  • anonymous
how do you get 3x-2
vijay
  • vijay
from 3x(x+3) -2(x+3), take out x-3, from 1st term 3x and 2nd term -2 is balance
anonymous
  • anonymous
because (x+3)(x+3) cancel out. leaving ONE (x+3) and whats left is 3x-2?
vijay
  • vijay
3x(x+3) -2(x+3) if u see front of (x+3),there is 3x and -2.
anonymous
  • anonymous
3x-2=0 x-2=0/3 x=3/1+2/1 x=6 x+3=0 x= -3 x= 3 x= 6
vijay
  • vijay
nope, 3x-2 = 0 and x+3=0 3x=2 x=-3 x=3/2
anonymous
  • anonymous
not x=2/3 ???
vijay
  • vijay
x = 2/3 is correct, if u substitute in to the function, it will satisfy.
anonymous
  • anonymous
ok so x= 2/3 x= -3
vijay
  • vijay
yes, that is the final answer, 100% correct
anonymous
  • anonymous
okay( thank you SOOO much!

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