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anonymous

  • 5 years ago

algebra 1b solve by factoring 3x squared + 7x-6=0

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  1. anonymous
    • 5 years ago
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    (3x - 2) (x + 2) = 0

  2. anonymous
    • 5 years ago
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    i mean (3x-2) ( x + 3)

  3. anonymous
    • 5 years ago
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    \[3x ^{2}+7x-6\]

  4. Vijay
    • 5 years ago
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    x=2/3 and -3

  5. anonymous
    • 5 years ago
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    how do you get that. i really need to understand

  6. anonymous
    • 5 years ago
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    trial and error you can also use quadratic equation

  7. Vijay
    • 5 years ago
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    3x^2 + 7x-6=0 3x^2 + 9x-2x-6=0 3x(x+3)-2(x+3)=0 (x+3)(3x-2)=0

  8. anonymous
    • 5 years ago
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    \[step 1. (x+9)(x-2) step 2??\]

  9. Vijay
    • 5 years ago
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    (x+3)(3x-2)=0 (x+3) = 0 and 3x-2 = 0 x = -3 and x = 2/3

  10. anonymous
    • 5 years ago
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    how did you get (x+3)(3x-2) ????

  11. Vijay
    • 5 years ago
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    from this line 3x(x+3)-2(x+3)=0 if u factorise (x+3) , u may get

  12. anonymous
    • 5 years ago
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    correction: how did you get \[3x ^{2}+7x-6=0\]

  13. anonymous
    • 5 years ago
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    sorry im confusing myself .

  14. anonymous
    • 5 years ago
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    my teacher makes us do a big x. so what multiplies to -12 and adds to 7. i got 9 and -2 so (x+9) (x-2) how do i go on from there

  15. Vijay
    • 5 years ago
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    can u type your question again with mathematical symbols ?

  16. anonymous
    • 5 years ago
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    solve by factoring \[3x ^{2}+7x-6=0\] step one. FACTOR. multiply -6 and 3 to get -18. now find what multiplies to -18 make sure that they also add to get 7. 9 and -2 MULTIPLY together and make -18 and ADD to make 7. so you make the equation (x+9)(x-2)=0 but you still have to do more for the rest of the problem. so im confused on the rest

  17. Vijay
    • 5 years ago
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    substitute your -9 and 2 for 7

  18. Vijay
    • 5 years ago
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    sorry 9 and -2

  19. anonymous
    • 5 years ago
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    so it would be \[3x ^{2}+(x+9)(x-2)-6=0 ?\] that makes no sense

  20. Vijay
    • 5 years ago
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    no, \[3x^2 +9x - 2x -6=0\]

  21. anonymous
    • 5 years ago
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    so what do i do to solve that? add like terms?

  22. Vijay
    • 5 years ago
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    then,. factorise 3x from from 1st two terms ans factorise 2 from last two terms

  23. anonymous
    • 5 years ago
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    3x(x+3) -2(x+3)

  24. Vijay
    • 5 years ago
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    yes, then factorise (x+3)

  25. anonymous
    • 5 years ago
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    wait so how to i solve the rest of the problem

  26. Vijay
    • 5 years ago
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    then, each of them equal to zero

  27. anonymous
    • 5 years ago
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    3x(x+3)=0 -2(x+3)=0

  28. Vijay
    • 5 years ago
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    no, when u factorise by ( x-3), u will get (x-3)(3x-2) = 0

  29. Vijay
    • 5 years ago
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    After that make, x-3 = 0 and 3x- 2 = 0

  30. anonymous
    • 5 years ago
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    howd you get (x-3) and (3x-2)

  31. Vijay
    • 5 years ago
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    from 3x(x+3) -2(x+3) = 0, factorise (x+3)

  32. Vijay
    • 5 years ago
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    take out x+3 , then 3x-2 is other balance

  33. anonymous
    • 5 years ago
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    how do you get 3x-2

  34. Vijay
    • 5 years ago
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    from 3x(x+3) -2(x+3), take out x-3, from 1st term 3x and 2nd term -2 is balance

  35. anonymous
    • 5 years ago
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    because (x+3)(x+3) cancel out. leaving ONE (x+3) and whats left is 3x-2?

  36. Vijay
    • 5 years ago
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    3x(x+3) -2(x+3) if u see front of (x+3),there is 3x and -2.

  37. anonymous
    • 5 years ago
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    3x-2=0 x-2=0/3 x=3/1+2/1 x=6 x+3=0 x= -3 x= 3 x= 6

  38. Vijay
    • 5 years ago
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    nope, 3x-2 = 0 and x+3=0 3x=2 x=-3 x=3/2

  39. anonymous
    • 5 years ago
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    not x=2/3 ???

  40. Vijay
    • 5 years ago
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    x = 2/3 is correct, if u substitute in to the function, it will satisfy.

  41. anonymous
    • 5 years ago
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    ok so x= 2/3 x= -3

  42. Vijay
    • 5 years ago
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    yes, that is the final answer, 100% correct

  43. anonymous
    • 5 years ago
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    okay( thank you SOOO much!

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