anonymous
  • anonymous
ok to find the derivative of f(x)=arctan(sqrt(3x-1)) i got all the way to 4/sqrt(-16x^2+8x)...that is wrong...what am i missing
Mathematics
jamiebookeater
  • jamiebookeater
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vijay
  • vijay
\[[ 1 / (1 + 3x -1 )] * 2 *3 * 1/\sqrt{3x-1}\]
vijay
  • vijay
\[[ 1 / (1 + 3x -1 )] * 1/2 *3 * 1/\sqrt{3x-1}\]
anonymous
  • anonymous
sorry vijay i meant i got that answer for the other problem i just posted can u look at the other one i just posted

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vijay
  • vijay
where did u post that ?
anonymous
  • anonymous
i just posted it
anonymous
  • anonymous
ooops,,,wrong problem...i meant i got that answer for f(x)=sin^-1(4x+1)
anonymous
  • anonymous
this is the problem that goes to the answer i got wrong

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