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anonymous

  • 5 years ago

f(x)=(1+16x^2)tan^-1(4x)...find the derivative...i got 128x/(1+16x^2)...its wrong...i keep missing a step

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  1. Vijay
    • 5 years ago
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    \[32x \tan^{-1} (4x) + 4\]

  2. anonymous
    • 5 years ago
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    how did u get that

  3. Vijay
    • 5 years ago
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    differentiation by parts

  4. anonymous
    • 5 years ago
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    but the derivative of tan^-1 is 1/1+x^2 and you plug 4x into for the x....anc then continue...what happened to that equation

  5. Vijay
    • 5 years ago
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    tan^-1(x) = 1/ 1 +x^2, but tan^-1(4x) = 4/(4^2 + x^2)

  6. anonymous
    • 5 years ago
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    ok so how did u get from that to the answer u gave

  7. anonymous
    • 5 years ago
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    i dont understand why you would use the derivative equation for one problem and not the other

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