anonymous
  • anonymous
-1/n + (m/n)^2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
What exactly are you required to do for this problem?
anonymous
  • anonymous
Im sorry only the m ^2. Solve by adding.
anonymous
  • anonymous
What class are you taking?

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More answers

anonymous
  • anonymous
I believe the answer is -1+m / n^3. The m wasnt ^2 it was the n. sorry im confusing. Prealgebra
anonymous
  • anonymous
OH okay...
anonymous
  • anonymous
-n+m^2 /n^2
anonymous
  • anonymous
I'm confused how you got that jamie. I'm gonna write the problem out again. It is -1/n + m/n^2
anonymous
  • anonymous
I have a prgram that does the problem for me if i type it in but let me check
anonymous
  • anonymous
yeah thats what i got.
anonymous
  • anonymous
Wow then I totally do not know what im doing. dang it
anonymous
  • anonymous
hahah download the program its really nice. its called algerbrator i think its 30$
anonymous
  • anonymous
I will look into that
anonymous
  • anonymous
lol
anonymous
  • anonymous
Thanks
anonymous
  • anonymous
if you're still confused, multiply -1/n by n/n (=1) then you'll have common denominators (n^2)
anonymous
  • anonymous
INT jamie said her answer is right and mine is wrong so i have been sitting here confused trying to figure it out
anonymous
  • anonymous
yeah, jamie is correct (-1/n)*(n/n)=(-n)/(n^2) [(-n)/(n^2)]+[(m^2)/(n^2)]=(m^2-n)/(n^2)
anonymous
  • anonymous
you can do this because n/n is just 1
anonymous
  • anonymous
Thanks so much

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