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anonymous
 5 years ago
The function f(x)=x/(2x+1) 5 will decrease by approximately 0.6 as x decreases from 3 to 2.7. TRUE OR FALSE. How do I show the work. Not sure where to start.
anonymous
 5 years ago
The function f(x)=x/(2x+1) 5 will decrease by approximately 0.6 as x decreases from 3 to 2.7. TRUE OR FALSE. How do I show the work. Not sure where to start.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just calculate the function when x = 3 and when x = 2.7. If f(3) is about .6 more than f(2.7), it's true

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't need to do the derivitive of the problem?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0The derivative is a rate of change; or how fast something is at a given point; how fast something is moving/changing. This question appears to be asking for a value of "how much" and not "how fast". But I could be mistaken... So I agree with dwob...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x is decreasing from 3 to 2.7. Would that not be a rate of change?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You technically could solve this with derivatives if you wanted to, but you'd find the derivative and then integrate it for no real reason. If I run and want to now how much weight I sweat off, I just weigh myself before and after. It's the same concept. Check the before (x = 3) and then check the after (x = 2.7) You don't need to know the speed that it sweat off (finding the derivative), just the total amount.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks for the info. All of the other problems I have to do, deals with the derivative, so I just assumed this one would too.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0The "slope" of the line at x=3 is .2245 The "slope" of the line at x=2.7 = .1997 So the slope of the line is increasing from 3 to 2.7 by .0252. But, that is not a decrease in f(x); it is a decrease in the slope of the line that is tangent to the curve at f(x) Either way, I would say it is false.
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