How do I solve the second order non homogeneous DE x''(t) = e^x -1 ?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ok so you would take -1 and add it to e^x then take x" and divide by (t) make sense allen_83?
forget about t . that's the rate of change with respect to time. for \[x'' = e^x\] there aint no problem. one can apply \[\lambda^2 = 0 \] and solve for the roots which are in my case 0 (i.e for the hom. part)and for the inhom. part equate the right hand side to \[Ce^x\] and solve for the constant C which turns out to be 1 and plug C back in and add hom. + inhom. to obtain a genral solution. However the question is what now with this \[e^x -1 \] ? how do I come up with a hint tosolve this equation ? and your suggestion makes no sense my frined. maybe it's time to start lovin math. ANY ideas ?