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anonymous

  • 5 years ago

How do I solve the second order non homogeneous DE x''(t) = e^x -1 ?

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  1. anonymous
    • 5 years ago
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    ok so you would take -1 and add it to e^x then take x" and divide by (t) make sense allen_83?

  2. anonymous
    • 5 years ago
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    forget about t . that's the rate of change with respect to time. for \[x'' = e^x\] there aint no problem. one can apply \[\lambda^2 = 0 \] and solve for the roots which are in my case 0 (i.e for the hom. part)and for the inhom. part equate the right hand side to \[Ce^x\] and solve for the constant C which turns out to be 1 and plug C back in and add hom. + inhom. to obtain a genral solution. However the question is what now with this \[e^x -1 \] ? how do I come up with a hint tosolve this equation ? and your suggestion makes no sense my frined. maybe it's time to start lovin math. ANY ideas ?

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