• anonymous
How do I solve the second order non homogeneous DE x''(t) = e^x -1 ?
  • jamiebookeater
I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this
and thousands of other questions

  • anonymous
ok so you would take -1 and add it to e^x then take x" and divide by (t) make sense allen_83?
  • anonymous
forget about t . that's the rate of change with respect to time. for \[x'' = e^x\] there aint no problem. one can apply \[\lambda^2 = 0 \] and solve for the roots which are in my case 0 (i.e for the hom. part)and for the inhom. part equate the right hand side to \[Ce^x\] and solve for the constant C which turns out to be 1 and plug C back in and add hom. + inhom. to obtain a genral solution. However the question is what now with this \[e^x -1 \] ? how do I come up with a hint tosolve this equation ? and your suggestion makes no sense my frined. maybe it's time to start lovin math. ANY ideas ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.