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anonymous
 5 years ago
5x3=12x+11
7(5p+3)49=2(3p+6)
4+3(4n+6)n
anonymous
 5 years ago
5x3=12x+11 7(5p+3)49=2(3p+6) 4+3(4n+6)n

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are those 3 separate questions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0give me some time to figure out number 2 and 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i keep on coming up with the wrong answer for all 3 of them and dont know how

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05x3=12x+11 First subtract 5x from both sides: 3 = 7x + 11 Subtract 11 from both sides: 14 = 7x Divide by 7 on both sides: x = 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i was trying to add 5 to both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh do you get the second one? or do you need explanation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do i add 7 to 2(3p+6)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you multiply: 7(5p) + 7(3) and that gives you an equation as: 35p + 2149 = 6p +6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so at the end your equation is 76 =9p and then you get the answer by dividing 9p to 76

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that what i got but i get 8.4 it does not look right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the third answer is 22 + 11n and i don't know if you want me to simplify it or keep it like this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmmm let me try the second answer again...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you get the third answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i did just before you posted it trying to work on 2
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