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anonymous

  • 5 years ago

solve the differential equation: dy/dx + (y^3 + 4e^xy)/(2e^x+3y^2)

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  1. anonymous
    • 5 years ago
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    can use bernoulli's method, linear, separable, homogenity test, etc.

  2. amistre64
    • 5 years ago
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    dy/dx + (y^3 +4e^xy)/(2e^x +3y^2) = 0 dy = -(y^3 +4e^xy)/(2e^x +3y^2) dx dy = -y(y^2 +4e^x)/(2e^x +3y^2) dx dy/-y(y^2 +4e^x) = dx/(2e^x +3y^2) Oww its giving me a headache :) Does that help any?

  3. anonymous
    • 5 years ago
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    yes but dx can only have functions of x with it and the same for y so is it not separable?

  4. amistre64
    • 5 years ago
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    It might be separable, but I cant see it yet :)

  5. anonymous
    • 5 years ago
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    the e^x is the problem

  6. anonymous
    • 5 years ago
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    i have an idea multiply all of them then take integral :)

  7. anonymous
    • 5 years ago
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    this is y^3 +4e^xy =u du/dy=2e^x+3y^2 may be this

  8. amistre64
    • 5 years ago
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    This ones outta my league for now....

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