anonymous
  • anonymous
i need help with the following problem:2.1q-4.7-1.8q=0.7q-4.8. can anyone help me work through this?
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Yes Goal: You want to combine like terms. What is a like term? Like terms are individual numbers that have like quantities. For instance, 2.1 q is a like term with 0.7q You want to simplify it by turning 2.1q and 0.7q into one number of (Coefficient)q Also, -4.7 and -4.8 are like terms. So the process: First simplify each side Left: 2.1q - 1.8q = .3q -4.7 = -4.7 Left side simplified: .3q - 4.7 Right: .7q - 4.8 is already simplified. Next, write the equation with both sides simplified: .3q - 4.7 = .7q - 4.8 Simplify like terms, one term at a time to prevent errors from rushing. -4.7 = .4q - 4.8 .1 = .4q Now divide .1 by .4 q = .25 I apologize if I had a math error, but I showed you the process so you should be able to fix it if I did. Always check your work.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.