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anonymous
 5 years ago
how can i do this 27z318z2+3z
anonymous
 5 years ago
how can i do this 27z318z2+3z

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0BG: Do you want to simplify that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok pull out any common terms. In your case, there are both coefficients and variables that are common. 27, 18, and 3 are all divisible by 3. Thus, 3(9z^36z^2+z) Also, z^3, z^2, and z^1 all have z^1 in common. Thus, 3z(9z^26z+1) is the most simplified form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0another way to do it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you clarify what you need?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.027z318z2+3z =( )( )( )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok So you want to factor the equation into three quantities. 3z * (3z1)^2 = 27z318z2+3z Thus, (3z)(3z1)(3z1) is your answer. An easier way to do this by hand (i factored it on my calculator) would be to follow my first method arriving at this answer: 3z(9z^26z+1) Then, you can more easily factor (9z^26z+1) into (3z1)^2 So then you have (3z)(3z1)(3z1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks and i am still brute

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and this one \[6x ^{2}+11x+4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(2x+1)(3x+4) Take the coefficient from 6x^2 (6) and break it into factors. The factors of 6 are 6,3,2,1 I normally pick the middle two. 3 and 2. Then make ( _x + _ ) ( _x + _ ) this setup Plug in ( 3x + _ ) ( 2x + _ ) then use guess and check for the two blanks that are factors of 4 and when expanded add to 11. This gives you (2x+1)(3x+4) Sometimes these problems can take a /long/ time.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what method did you use
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