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anonymous
 5 years ago
EVALUATE ALGEBRAICALLY LIM 3X^2 +2X 2/ 2X^2  1 AS X GOES TO INFINITY
anonymous
 5 years ago
EVALUATE ALGEBRAICALLY LIM 3X^2 +2X 2/ 2X^2  1 AS X GOES TO INFINITY

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0try this again.... Use the largest exponent value of "x" from the denominator to divide everything you have. In your case, it is (x^2) top: 3x^2/x^2 +2x/x^2 2/x^2 becomes: 3 +2/x 2/x^2 toss away anything with an x in the denominator because it goes to 0 as x goes to infinity. top = 3 bottom: 2x^2/x^2 1/x^2 becomes: 2 1/x^2  toss out anything with an x in the denominator because it will go to 0 as x goes to infinity. bottom = 2 so the limit is (3/2) as x > infinity

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Rules that you discover are: If the highest exponent of "x" is in the bottom; the limit =0 example: 2x/3x^2 has a limit of 0 If the highest exponent is the same from top to bottom; the limit is the value of the leading cooeficients. Example: 5x^3/3x^3 limit is 5/3 If highest exponent is on top; then you have an "oblique" asymptote (kind of a limit but not). example: 6x^2/2x = 6x as an asymptote. the ends of the graph will approach a line of (y=6x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THANK YOU U MAKE IT VERY CLEAR TO ME
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