EVALUATE ALGEBRAICALLY LIM 3X^2 +2X -2/ 2X^2 - 1 AS X GOES TO INFINITY

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EVALUATE ALGEBRAICALLY LIM 3X^2 +2X -2/ 2X^2 - 1 AS X GOES TO INFINITY

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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try this again.... Use the largest exponent value of "x" from the denominator to divide everything you have. In your case, it is (x^2) top: 3x^2/x^2 +2x/x^2 -2/x^2 becomes: 3 +2/x -2/x^2 --toss away anything with an x in the denominator because it goes to 0 as x goes to infinity. top = 3 bottom: 2x^2/x^2 -1/x^2 becomes: 2 -1/x^2 -- toss out anything with an x in the denominator because it will go to 0 as x goes to infinity. bottom = 2 so the limit is (3/2) as x --> infinity
Rules that you discover are: If the highest exponent of "x" is in the bottom; the limit =0 example: 2x/3x^2 has a limit of 0 If the highest exponent is the same from top to bottom; the limit is the value of the leading cooeficients. Example: 5x^3/3x^3 limit is 5/3 If highest exponent is on top; then you have an "oblique" asymptote (kind of a limit but not). example: 6x^2/2x = 6x as an asymptote. the ends of the graph will approach a line of (y=6x)
THANK YOU U MAKE IT VERY CLEAR TO ME

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