anonymous
  • anonymous
EVALUATE ALGEBRAICALLY LIM 3X^2 +2X -2/ 2X^2 - 1 AS X GOES TO INFINITY
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
try this again.... Use the largest exponent value of "x" from the denominator to divide everything you have. In your case, it is (x^2) top: 3x^2/x^2 +2x/x^2 -2/x^2 becomes: 3 +2/x -2/x^2 --toss away anything with an x in the denominator because it goes to 0 as x goes to infinity. top = 3 bottom: 2x^2/x^2 -1/x^2 becomes: 2 -1/x^2 -- toss out anything with an x in the denominator because it will go to 0 as x goes to infinity. bottom = 2 so the limit is (3/2) as x --> infinity
amistre64
  • amistre64
Rules that you discover are: If the highest exponent of "x" is in the bottom; the limit =0 example: 2x/3x^2 has a limit of 0 If the highest exponent is the same from top to bottom; the limit is the value of the leading cooeficients. Example: 5x^3/3x^3 limit is 5/3 If highest exponent is on top; then you have an "oblique" asymptote (kind of a limit but not). example: 6x^2/2x = 6x as an asymptote. the ends of the graph will approach a line of (y=6x)
anonymous
  • anonymous
THANK YOU U MAKE IT VERY CLEAR TO ME

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