Gina
  • Gina
find Bernoulli's equation,,,,, xy'-ytgx+y^2cosx=0
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I'm assuming t and g are constants? I'm also assuming that y is a function of x, i.e. one variable? Otherwise you'll have to do this as a partial differential equation (PDE) which I'm not familiar with and is rather difficult.
anonymous
  • anonymous
If this is true, then it's not very difficult except for the integration.
Gina
  • Gina
thn help plz

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anonymous
  • anonymous
Well, are they constants?
anonymous
  • anonymous
Sorry, are t and g constants that is?
anonymous
  • anonymous
Well, assuming t and g are constants, the Bernoulli equation would be this \[xy \prime-ytgx=y^{2}cosx\]\[y \prime - ytg=y^{2}\cos(x)/x\] However, trying to solve this equation will quickly make your head hurt as it looks like it involves the exponential integral which I know nothing about. I'll ask one of the math professors at my school tomorrow. However, the Bernoulli equation (unsolved) is what I wrote above.

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