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Gina

  • 5 years ago

find Bernoulli's equation,,,,, xy'-ytgx+y^2cosx=0

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  1. anonymous
    • 5 years ago
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    I'm assuming t and g are constants? I'm also assuming that y is a function of x, i.e. one variable? Otherwise you'll have to do this as a partial differential equation (PDE) which I'm not familiar with and is rather difficult.

  2. anonymous
    • 5 years ago
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    If this is true, then it's not very difficult except for the integration.

  3. Gina
    • 5 years ago
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    thn help plz

  4. anonymous
    • 5 years ago
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    Well, are they constants?

  5. anonymous
    • 5 years ago
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    Sorry, are t and g constants that is?

  6. anonymous
    • 5 years ago
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    Well, assuming t and g are constants, the Bernoulli equation would be this \[xy \prime-ytgx=y^{2}cosx\]\[y \prime - ytg=y^{2}\cos(x)/x\] However, trying to solve this equation will quickly make your head hurt as it looks like it involves the exponential integral which I know nothing about. I'll ask one of the math professors at my school tomorrow. However, the Bernoulli equation (unsolved) is what I wrote above.

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