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anonymous
 5 years ago
find Bernoulli's equation,,,,, xy'ytgx+y^2cosx=0
anonymous
 5 years ago
find Bernoulli's equation,,,,, xy'ytgx+y^2cosx=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm assuming t and g are constants? I'm also assuming that y is a function of x, i.e. one variable? Otherwise you'll have to do this as a partial differential equation (PDE) which I'm not familiar with and is rather difficult.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If this is true, then it's not very difficult except for the integration.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, are they constants?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, are t and g constants that is?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, assuming t and g are constants, the Bernoulli equation would be this \[xy \primeytgx=y^{2}cosx\]\[y \prime  ytg=y^{2}\cos(x)/x\] However, trying to solve this equation will quickly make your head hurt as it looks like it involves the exponential integral which I know nothing about. I'll ask one of the math professors at my school tomorrow. However, the Bernoulli equation (unsolved) is what I wrote above.
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