## Gina 5 years ago find Bernoulli's equation,,,,, xy'-ytgx+y^2cosx=0

1. anonymous

I'm assuming t and g are constants? I'm also assuming that y is a function of x, i.e. one variable? Otherwise you'll have to do this as a partial differential equation (PDE) which I'm not familiar with and is rather difficult.

2. anonymous

If this is true, then it's not very difficult except for the integration.

3. Gina

thn help plz

4. anonymous

Well, are they constants?

5. anonymous

Sorry, are t and g constants that is?

6. anonymous

Well, assuming t and g are constants, the Bernoulli equation would be this $xy \prime-ytgx=y^{2}cosx$$y \prime - ytg=y^{2}\cos(x)/x$ However, trying to solve this equation will quickly make your head hurt as it looks like it involves the exponential integral which I know nothing about. I'll ask one of the math professors at my school tomorrow. However, the Bernoulli equation (unsolved) is what I wrote above.