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  • 5 years ago

A man invests $6000 in two accounts. The first account pays 5% simple interest and the second pays 8.5% simple interest. Together the investments earn $370 per year. How much of the $6000 is invested at 5%?

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  1. anonymous
    • 5 years ago
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    let A be the amount invested at 1st account and B amount invested in 2nd account. now we have equations: (1) A+B=6000 [because sums invested in both account is $6000] (2) (5/100)*A + (8.5/100)*B = 370 [because he earn $370 from both accounts] solve the equations, substitute B from (1) into (2), you can get A. which is the anwer required.

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