I need help on how to solve this problem and how to set it up. 3^(3x-1)=9(x-3)

I need help on how to solve this problem and how to set it up. 3^(3x-1)=9(x-3)

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Typo on last post it should be: 3^(3x-1)=9^(x-3)

first u note that 9^(x-3) = 3^[2(x-3)]
therefore;
3x-1=2(x-3). solve this to get x.

where did the two come from?

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