anonymous
  • anonymous
SIMPLIFY : square root of 27x^8y^5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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vijay
  • vijay
\[3y^2 x^4 \sqrt{3y}\]
anonymous
  • anonymous
?
anonymous
  • anonymous
can you explain how you got that please!

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vijay
  • vijay
\[\sqrt{3*3^2*(x^4)^2*(y^2)^2*y}\]
anonymous
  • anonymous
in words.... please
anonymous
  • anonymous
from your final answer in words can you please explain what you did.. i am looking for explinations.
vijay
  • vijay
After that , when you square root them , power 2 will ignore by sqrt. then 3 and y will be inside the sqrt ., others will come out.
anonymous
  • anonymous
no i mean from the begining please!
anonymous
  • anonymous
so looking at the equation what is the first step that i would taking in simplifying it?
Preetha
  • Preetha
I think what Vijay did was to break each term down into something x a square. So 27 is 3 x (3x3) or 3 x 3^2. x^8 is x^4 squared. And y^5 is y^4 x y.
vijay
  • vijay
Thanks preetha
Preetha
  • Preetha
Then you take the square root of this equation he has written out so nicely with the equation editor. So if you have 3 x (3x3) the sq. root of that is sqrt 3 (3), sqrt of (x4)^2 is x^4 and sqrt of y(y^4) is sqrt y (y^2).
Preetha
  • Preetha
Then you put the three terms together. Hope that helps. I am just too lazy to use the equation editor. Good job Vijay.
anonymous
  • anonymous
hello?
vijay
  • vijay
yes
anonymous
  • anonymous
nevermind i got it ! thanks. but here is one : twelve network printers can produce a set of documents in 20 hours. how long would it take 15 printers to get the same job done? (the time is inversly proportional tot the # of printers used for job)
vijay
  • vijay
=(20/12) * 15 =25 hours
anonymous
  • anonymous
why did you multiply by 15?
anonymous
  • anonymous
the answer says 16 hrs... i am unsure how the book got that.
vijay
  • vijay
yes, 25 is wrong, wait i l do it
anonymous
  • anonymous
i got it. 15/12 = 20/x 15x= 12*20 15/240 = 16
vijay
  • vijay
yes, gud
anonymous
  • anonymous
hey i just posted something do you know how to factor?

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