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anonymous
 5 years ago
SIMPLIFY : square root of 27x^8y^5
anonymous
 5 years ago
SIMPLIFY : square root of 27x^8y^5

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[3y^2 x^4 \sqrt{3y}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you explain how you got that please!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{3*3^2*(x^4)^2*(y^2)^2*y}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0from your final answer in words can you please explain what you did.. i am looking for explinations.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0After that , when you square root them , power 2 will ignore by sqrt. then 3 and y will be inside the sqrt ., others will come out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i mean from the begining please!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so looking at the equation what is the first step that i would taking in simplifying it?

Preetha
 5 years ago
Best ResponseYou've already chosen the best response.0I think what Vijay did was to break each term down into something x a square. So 27 is 3 x (3x3) or 3 x 3^2. x^8 is x^4 squared. And y^5 is y^4 x y.

Preetha
 5 years ago
Best ResponseYou've already chosen the best response.0Then you take the square root of this equation he has written out so nicely with the equation editor. So if you have 3 x (3x3) the sq. root of that is sqrt 3 (3), sqrt of (x4)^2 is x^4 and sqrt of y(y^4) is sqrt y (y^2).

Preetha
 5 years ago
Best ResponseYou've already chosen the best response.0Then you put the three terms together. Hope that helps. I am just too lazy to use the equation editor. Good job Vijay.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nevermind i got it ! thanks. but here is one : twelve network printers can produce a set of documents in 20 hours. how long would it take 15 printers to get the same job done? (the time is inversly proportional tot the # of printers used for job)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0=(20/12) * 15 =25 hours

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why did you multiply by 15?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer says 16 hrs... i am unsure how the book got that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, 25 is wrong, wait i l do it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got it. 15/12 = 20/x 15x= 12*20 15/240 = 16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey i just posted something do you know how to factor?
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