anonymous
  • anonymous
Suppose you have 80 ft. of fence to enclose a rectangular garden. the function A=40x-x squared, gives you the area of the garden in square feet where x is the width in feet . a. What width gives you the maximum gardening area? b. What is the maximum area?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
NEED HELP
anonymous
  • anonymous
IAM FAILING
anonymous
  • anonymous
is something wrong with your question.. I am figuring out and there is some mistake I found out in A=40x-x ???? Check it out again

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anonymous
  • anonymous
is something wrong with your question.. I am figuring out and there is some mistake I found out in A=40x-x ???? Check it out again
anonymous
  • anonymous
A=40x-x squared is the equation
anonymous
  • anonymous
Calm down, the maximum area will be a square so the side will be 20 set A = 80 and solve for x
anonymous
  • anonymous
I dont knoow how to do the square thingy
anonymous
  • anonymous
But what is A in the equation
anonymous
  • anonymous
\[\sqrt{80}=40x-x\]
anonymous
  • anonymous
Is it Y
anonymous
  • anonymous
I dont get how to get x that is the problem
anonymous
  • anonymous
Can you go step by step for me to get it
anonymous
  • anonymous
sorry, x is width in ft, so actually the equation should be A=40(20)-20 since width should be 20
anonymous
  • anonymous
ohhh
anonymous
  • anonymous
(40(20)-20)^2=A
anonymous
  • anonymous
the equation is A=40x-x.. so.. it just left.. A=30x.. right... and every each side is 20 for the whole Area.... I gree with Rouault..... That is the same thing.. But.. the equation might be.. A=40x^2-x... I think...
anonymous
  • anonymous
so would it be 400 is the maximum area as 20 is the width that gives me the maximum area
anonymous
  • anonymous
is my anwser correct

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