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anonymous

  • 5 years ago

Suppose you have 80 ft. of fence to enclose a rectangular garden. the function A=40x-x squared, gives you the area of the garden in square feet where x is the width in feet . a. What width gives you the maximum gardening area? b. What is the maximum area?

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  1. anonymous
    • 5 years ago
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    NEED HELP

  2. anonymous
    • 5 years ago
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    IAM FAILING

  3. anonymous
    • 5 years ago
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    is something wrong with your question.. I am figuring out and there is some mistake I found out in A=40x-x ???? Check it out again

  4. anonymous
    • 5 years ago
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    is something wrong with your question.. I am figuring out and there is some mistake I found out in A=40x-x ???? Check it out again

  5. anonymous
    • 5 years ago
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    A=40x-x squared is the equation

  6. anonymous
    • 5 years ago
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    Calm down, the maximum area will be a square so the side will be 20 set A = 80 and solve for x

  7. anonymous
    • 5 years ago
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    I dont knoow how to do the square thingy

  8. anonymous
    • 5 years ago
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    But what is A in the equation

  9. anonymous
    • 5 years ago
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    \[\sqrt{80}=40x-x\]

  10. anonymous
    • 5 years ago
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    Is it Y

  11. anonymous
    • 5 years ago
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    I dont get how to get x that is the problem

  12. anonymous
    • 5 years ago
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    Can you go step by step for me to get it

  13. anonymous
    • 5 years ago
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    sorry, x is width in ft, so actually the equation should be A=40(20)-20 since width should be 20

  14. anonymous
    • 5 years ago
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    ohhh

  15. anonymous
    • 5 years ago
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    (40(20)-20)^2=A

  16. anonymous
    • 5 years ago
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    the equation is A=40x-x.. so.. it just left.. A=30x.. right... and every each side is 20 for the whole Area.... I gree with Rouault..... That is the same thing.. But.. the equation might be.. A=40x^2-x... I think...

  17. anonymous
    • 5 years ago
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    so would it be 400 is the maximum area as 20 is the width that gives me the maximum area

  18. anonymous
    • 5 years ago
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    is my anwser correct

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spraguer (Moderator)
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