A ball is thrown into the air with an upward velocity of 40 ft/s. Its height h in feet after t seconds is given by the function h=-16t^2+40t+6.
A. In how many seconds does the ball reach its maximum height?
B. What's the ball's maximum height?

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A) h'(t) = -32t + 40 = 0
-32t = -40
t = 5/4

Test if it's max or min:
h" = -32 < 0 therefore it's max

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