- anonymous

A ball is thrown into the air with an upward velocity of 40 ft/s. Its height h in feet after t seconds is given by the function h=-16t^2+40t+6.
A. In how many seconds does the ball reach its maximum height?
B. What's the ball's maximum height?

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- bahrom7893

A) h'(t) = -32t + 40 = 0
-32t = -40
t = 5/4

- bahrom7893

Test if it's max or min:
h" = -32 < 0 therefore it's max

- bahrom7893

B) The ball's maximum height therefore occurs at t = 5/4 and the height is:
h(5/4) = -16(5/4)^2 + 40(5/4) +6

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

wait i dont get what you are doing in the first slide

- bahrom7893

Taking the derivative of the function.

- bahrom7893

Did you take calculus?

- anonymous

Yah but you cant square the 32 yet you have to find the t first

- anonymous

no this is Algerbra advance

- bahrom7893

sorry nanas.. I am doing everything correct, but I don't know how to do this using algebra. Wait actually if u use algebra, just plot the graph.. look at it's highest point, x-value will be the time and y-value will be the height.. This is a parabola pointing down..

- bahrom7893

I was using calculus and my method works too, but if u don't know it i can just give u answers..

- anonymous

I tried that i guess my brain is to advanced lol
no I dont get how to plo the points but the anwser would be fine

- anonymous

i mean how to plot

- bahrom7893

just type in the equation and then use trace..
well the answers would be:
A) 5/4
B) -16 * (5/4) ^2 + 40 * (5/4) + 6 <=whatever that equals.. sorry don't feel like doin arithmetic right now.. i actually gotta go to bed lol got a class early 2morro..

- vijay

t = 10 secs

- anonymous

wow what time is it there

- bahrom7893

vijay can't be..

- bahrom7893

10:30 pm

- vijay

02:30 A.M.

- anonymous

wow its only 7 30 here

- bahrom7893

vijay t = 10 secs doesn't make sense.. it's t = 5/4

- vijay

if u use equation v=u+ft
v=0, u=40, f= -10, t= ?

- anonymous

ok What is the lil star thing

- bahrom7893

he is asking maximum height..

- bahrom7893

little star is multiplication

- bahrom7893

time at max height..

- vijay

1st find the time, then plug the t into the function, u will get height

- anonymous

bahrom is right i remember my online teacher saying this

- anonymous

oh so all i got to do is the multiplication

- bahrom7893

Okay here's proof:
At t = 10;
h = -16*(10)^2+40*10+6 = -1600 + 400 + 6 is less than 0.. u can't have a negative maximum height.. the ball is still in the air..

- bahrom7893

yeah just plug in 5/4 for t in the h(t) equation and find the answer..

- bahrom7893

Please click on become a fan if I helped, I really want to get to the next level!! Thanks =)
I'm off..

Looking for something else?

Not the answer you are looking for? Search for more explanations.