anonymous
  • anonymous
A ball is thrown into the air with an upward velocity of 40 ft/s. Its height h in feet after t seconds is given by the function h=-16t^2+40t+6. A. In how many seconds does the ball reach its maximum height? B. What's the ball's maximum height?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
bahrom7893
  • bahrom7893
A) h'(t) = -32t + 40 = 0 -32t = -40 t = 5/4
bahrom7893
  • bahrom7893
Test if it's max or min: h" = -32 < 0 therefore it's max
bahrom7893
  • bahrom7893
B) The ball's maximum height therefore occurs at t = 5/4 and the height is: h(5/4) = -16(5/4)^2 + 40(5/4) +6

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More answers

anonymous
  • anonymous
wait i dont get what you are doing in the first slide
bahrom7893
  • bahrom7893
Taking the derivative of the function.
bahrom7893
  • bahrom7893
Did you take calculus?
anonymous
  • anonymous
Yah but you cant square the 32 yet you have to find the t first
anonymous
  • anonymous
no this is Algerbra advance
bahrom7893
  • bahrom7893
sorry nanas.. I am doing everything correct, but I don't know how to do this using algebra. Wait actually if u use algebra, just plot the graph.. look at it's highest point, x-value will be the time and y-value will be the height.. This is a parabola pointing down..
bahrom7893
  • bahrom7893
I was using calculus and my method works too, but if u don't know it i can just give u answers..
anonymous
  • anonymous
I tried that i guess my brain is to advanced lol no I dont get how to plo the points but the anwser would be fine
anonymous
  • anonymous
i mean how to plot
bahrom7893
  • bahrom7893
just type in the equation and then use trace.. well the answers would be: A) 5/4 B) -16 * (5/4) ^2 + 40 * (5/4) + 6 <=whatever that equals.. sorry don't feel like doin arithmetic right now.. i actually gotta go to bed lol got a class early 2morro..
vijay
  • vijay
t = 10 secs
anonymous
  • anonymous
wow what time is it there
bahrom7893
  • bahrom7893
vijay can't be..
bahrom7893
  • bahrom7893
10:30 pm
vijay
  • vijay
02:30 A.M.
anonymous
  • anonymous
wow its only 7 30 here
bahrom7893
  • bahrom7893
vijay t = 10 secs doesn't make sense.. it's t = 5/4
vijay
  • vijay
if u use equation v=u+ft v=0, u=40, f= -10, t= ?
anonymous
  • anonymous
ok What is the lil star thing
bahrom7893
  • bahrom7893
he is asking maximum height..
bahrom7893
  • bahrom7893
little star is multiplication
bahrom7893
  • bahrom7893
time at max height..
vijay
  • vijay
1st find the time, then plug the t into the function, u will get height
anonymous
  • anonymous
bahrom is right i remember my online teacher saying this
anonymous
  • anonymous
oh so all i got to do is the multiplication
bahrom7893
  • bahrom7893
Okay here's proof: At t = 10; h = -16*(10)^2+40*10+6 = -1600 + 400 + 6 is less than 0.. u can't have a negative maximum height.. the ball is still in the air..
bahrom7893
  • bahrom7893
yeah just plug in 5/4 for t in the h(t) equation and find the answer..
bahrom7893
  • bahrom7893
Please click on become a fan if I helped, I really want to get to the next level!! Thanks =) I'm off..

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