A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
find the eq. to the tangent line and the normal line to the curve y= x+ square root of x, (1,2)
anonymous
 5 years ago
find the eq. to the tangent line and the normal line to the curve y= x+ square root of x, (1,2)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dy/dx= 1+1/square root of x. at (1,2) dy/dx=2=slope of tangent. and 1/2=slope of normal. equation of tangent, y2=2(x1). equation of normal, y2=1/2(x1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if u change the square into exponential u will have (x)^1/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry dy/ dx= 1+1/2squre root of x at (1,2) slope of tangent = 3/2..now you can solve ... i just missed 1/2 i above solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u have dy/dx=1+1/2square root of x^1/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that give u that give u 5/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you put 1 at the place of x you wil get. 1+1/2 sruare root of 1. now 1+1/2=3/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea but when u take the derivative of (x)^1/2 you will get 1/2(x)1/21 = to 1/2 (x)1/2... now u plug 1
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.