anonymous 5 years ago implicity 4cosxsiny=1

1. anonymous

$4\cos(x)\sin(y)=1$$\cos(x)\sin(y)=1/4$$d/dx(\cos(x)\sin(y))=d/dx(1/4)$$d/dx(\cos(x)\sin(y))=0$$-\sin(x)\sin(y)+\cos(x)\cos(y)dy/dx=0$ To get to the above equation I used product rule and to derive sin(y) I used chain rule, i.e. derivative of sin with y plugged in times the derivative of y.$dy/dx=\sin(x)\sin(y)/\cos(x)\cos(y)=\tan(x)\tan(y)$

2. anonymous

ok, so if i have a numer in front of sin x i just move it to the other side?