tan-1 (-1/square3)

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tan-1 (-1/square3)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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You have to make the identification,\[y=\tan^{-1}\left( -\frac{1}{\sqrt{3}} \right) \rightarrow \tan{y}=-\frac{1}{\sqrt{3}}\]If you know your exact trig. solutions (in this case, those obtained by cutting an equilateral triangle in half), tan(y)=1/sqrt(3) when y = 30 degrees. But we want the negative situation. Tan is negative in the second and fourth quadrants, so our angle will lie there. For the second quadrant, we get, 180-30 degrees = 150 degrees = 5pi/3 radians and 360-30 degrees = 330 degrees = 11pi/6 radians assuming you only want solutions for 0 <= y < 2pi

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