anonymous
  • anonymous
logx^1/64 =-3/2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Assuming I interpret your notation correctly,\[\log{x^{\frac{1}{64}}}=-\frac{3}{2}\rightarrow \frac{1}{64}\log{x}=-\frac{3}{2}\]So\[\log{x}=64 \times -\frac{3}{2}=-96\]Hence,\[x=e^{-96}\]
anonymous
  • anonymous
This is log base 10 not log base e or natural log so the answer should be: \[x=10^{-96}\]
anonymous
  • anonymous
Doesn't have to be.

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anonymous
  • anonymous
Yeah it does unless you change the base for x. log and ln are not equivalent. put it in a TI-89 or some math program
anonymous
  • anonymous
Well, it's a matter of definition. Log is technically the notation for natural logarithm in general, with ln reserved for use as the natural logarithm of the magnitude of a complex number. It's semantics. Mathematicians use log.
anonymous
  • anonymous
in maths log means base 10 not e unless it is mentioned.
anonymous
  • anonymous
Whatever. I have a degree + postgrad. in the subject. I'm not arguing about it anymore. Mathematicians use log for ln unless the base is made explicit.
anonymous
  • anonymous
srry then.

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